x/3+2+[x-(x/3+2)]/2-1+38=x X等于多少?

问题描述:

x/3+2+[x-(x/3+2)]/2-1+38=x X等于多少?

x/3+2+[x-(x/3+2)]/2-1+38=x
2x+12+3x-x-6-6+228=6x
2x=228
x=114