用加减消元法解下列方程1.x+y=201.4/100x+3.7/100y=0.6252.(2x-1)/5+(3y-2)/4=2(3x+1)/3-(3y+2)/4=4/33.x/2+(y/3)=22x+3x=28
问题描述:
用加减消元法解下列方程
1.x+y=20
1.4/100x+3.7/100y=0.625
2.(2x-1)/5+(3y-2)/4=2
(3x+1)/3-(3y+2)/4=4/3
3.x/2+(y/3)=2
2x+3x=28
答