已知函数f(z)=2z+z2+(1+i),则f(i)的值是_.

问题描述:

已知函数f(z)=2z+z2+(1+i),则f(i)的值是______.

∵f(z)=2z+z2+(1+i),
∴f(i)=2i+i2+(1+i)
=2i-1+1+i
=3i.
故答案为:3i.