用分解因式法解方程:2(x-3)=x2-9.一定要分解因式法!
问题描述:
用分解因式法解方程:2(x-3)=x2-9.一定要分解因式法!
答
2(x-3)=x平方-9
x平方-2x-3=0
(x-3)(x+1)=0
X1=3 x2=-1
答
2(x-3)=x²-9
2(x-3)=(x+3)(x-3)
(x-3)(x+3-2)=0
x=3 x=-1
答
2(x-3)=x²-9
(x²-9)-2(x-3)=0
(x-3)(x+3)-2(x-3)=0
(x-3)[(x+3)-2]=0
(x-3)(x+1)=0
x-3=0 或 x+1=0
x1=3
x2=-1
答
2﹙x-3﹚-﹙x-3﹚﹙x+3﹚=0
﹙x-3﹚﹙2-x-3﹚=0
﹙x-3﹚﹙x-1﹚=0
x1=3
x2=1