log(5)(x²+2x-3)=0的定义域.

问题描述:

log(5)(x²+2x-3)=0的定义域.

log(5)(x²+2x-3)=0,这是一个对数方程,等价于:(x²+2x-3)=1如果是:求log(5)(x²+2x-3)的定义域,则有:x²+2x-3>0(x+3)(x-1)>0x1log(5)(x²+2x-3)的定义域为:(-∞,-3)∪(1,∞)...