解方程：(2005x)的平方-2004乘2006x-1=0初三数学——一元二次方程（因式分解法）

(2005x)^2-(2005-1)(2005+1)x-1=0
2005^2*x^2-(2005^2-1)x-1=0
2005^2*x^2-2005^x+x-1=0
2005^2*x*(x-1)+x-1=0
(2005^2*x+1)(x-1)=0
∴x=-1/2005^2,或者x=1

(2005x)^2-2004*2006x-1=0
(2005x)^2-(2005^2 -1)x-1=0
[(2005^2)x+1](x-1)=0
x1=-1/2005^2, x2=1

2005^2x^2-2004*2006x-1=0
2005^2x^2-(2005-1)*(2005+1)x-1=0
2005^2x^2-(2005^2-1)x-1=0
(2005^2x+1)(x-1)=0
x=-1/2005^2或1