log2x+log4x+log8x=11 求x
问题描述：
log2x+log4x+log8x=11 求x
答
原式=log2x+log(2)^2(x)^1+log(2^3)(x)^1
=log2x+(1/2)log2x+(1/3)log2x
=(11/6)log2x=11
所以log2x=6得x=64