(5分之2MN^3-MN^2+6分之1N^5)/(-3分之2 N^2)
问题描述:
(5分之2MN^3-MN^2+6分之1N^5)/(-3分之2 N^2)
答
(2/5*MN^3-MN^2+1/6*N^5)/(-2/3*N^2)
=(2/5*MN-M+1/6*N^3)/(-2/3)
=(2/5*MN-M+1/6*N^3)*(-3/2)
=-3/5*MN+3/2*M-1/4*N^3