待定系数法因式分解6x平方+13xy+6y平方+5x+5y+1
问题描述：
待定系数法因式分解6x平方+13xy+6y平方+5x+5y+1
答
令6x^2+13xy+6y^2+5x+5y+1=(ax+by+c)(dx+ey+f)6x^2+13xy+6y^2+5x+5y+1=(ax+by+c)(dx+ey+f)=adx^2+(ae+bd)xy+(af+cd)x+bey^2+(bf+ce)y+cf对比,得ad=6ae+bd=13af+cd=5bf+ce=5cf=1be=6解得a=2b=3c=1d=3e=2f=16x^2+13xy+...