计算(根号3/2i-1/2)(-1/2+根号3/2i)

问题描述:

计算(根号3/2i-1/2)(-1/2+根号3/2i)

(根号3/2i-1/2)(-1/2+根号3/2i)=(√3/2i-1/2)²=(-√3i/2-1/2)²=(√3i+1)²/4
=(3i²+2√3i+1)/4=(-2+2√3i)/4=-1/2+√3i/2