已知xy=-2,X+Y=3,求(5Xy+10y)+[5X-(3Xy+2Y-3x)]的值

问题描述:

已知xy=-2,X+Y=3,求(5Xy+10y)+[5X-(3Xy+2Y-3x)]的值

等于20先打开括号得2XY+8(X+Y)之后把条件代入就好

(5Xy+10y)+[5X-(3Xy+2Y-3X)]
= 5Xy+10y + 5X-3Xy-2Y+3X
= 2Xy+8y + 8X
= 2Xy + 8(X+y)
= 2*(-2) + 8*3
= 20

(5Xy+10y)+[5X-(3Xy+2Y-3x)]
=5Y(X+2)+(5X-3XY-2Y+3X)
=5YX+10Y+8X-3XY-2Y
=2XY+8Y+8X
=2*-2+8(x+y)
=-4+24
=20