函数求导 y=cos^2(2x+圆周率/3)
问题描述:
函数求导 y=cos^2(2x+圆周率/3)
答
y=2cos(2x+π/3)* [-sin(2x+π/3)]*2
=-4cos(2x+π/3)sin(2x+π/3)
=-2sin(4x+2π/3)
答
y’=2cos(2x+π/3)* [cos(2x+π/3)]‘=2cos(2x+π/3)* [-2sin(2x+π/3)]
=-4cos(2x+π/3)sin(2x+π/3)
=-2sin(4x+2π/3)