若a与b互为相反数,x与y互为倒数.m=-(-3),求2m/xy,+a+b/2011的值
问题描述：
若a与b互为相反数,x与y互为倒数.m=-(-3),求2m/xy,+a+b/2011的值
答
a+b=0
x*y=1
m=3
2m/xy
=6/1
=6
+a+b/2011
=0/2011
=0
答
6
答
∵a与b互为相反数,x与y互为倒数.m=-(-3),
∴a+b=0 xy=1 m=3
∴2m/xy+(a+b)/2011=2*3/1+0/2011=6