先化简,再求值:(x-2分之x-x+2分之x)除以x-2分之4x,其中x=-4
问题描述:
先化简,再求值:(x-2分之x-x+2分之x)除以x-2分之4x,其中x=-4
答
:(x-2分之x-x+2分之x)除以x-2分之4x
=[x(x+2)-x(x-2)]/(x+2)(x-2)×(x-2)/4x
=4x/(x+2)(x-2)×(x-2)/4x
=1/(x+2)
当x=-4时原式=1/(x+2)=1/(-4+2)=-1/2
答
[x/(x-2)-x/(x+2)]÷[4x/(x-2)]
=[x(x+2)-x(x-2)]/[(x-2)(x+2)]×[(x-2)/4x]
=4x/[(x-2)(x+2)]×[(x-2)/4x]
=1/(x+2)
=1/(-4+2)
=-1/2