2x^2-π（x/2）^2=180 解这个方程,结果保留π.两个根都要,
问题描述：
2x^2-π（x/2）^2=180 解这个方程,结果保留π.两个根都要,
答
2x^2-π（x^2/4)=180
x^2(2-π/4)=180
x^2=180/(2-π/4)
x=±根号[180/(2-π/4)]
=±根号[720/(8-π)]
=±12根号[5/(8-π)]
答
2x^2 - π(x/2)^2 = 180
8x^2 - πx^2 = 720
x^2(8 - π) = 720
x^2 = 720 / (8 - π)
x = ±√ [720 / (8 - π)]
进一步化简,分母有理化,得
x = ±12√ [5(8 - π)] / (8 - π)