若x-y=1,xy=1,则5x的二次方+5y的二次方的值为

问题描述:

若x-y=1,xy=1,则5x的二次方+5y的二次方的值为

5x的二次方+5y的二次方
=5(x²+y²)
=5(x-y)²+10xy
=5*1²+10*1
=5+10
=15

5x的二次方+5y的二次方
=5[(x-y)^2+2xy]
=5(1^2+2×1)
=15

x-y=1
(x-y)²=1
x²-2xy+y²=1
x²+y²=1+2xy=3
5(x²+y²)=15
5x的二次方+5y的二次方的值为15

5x²+5y²
=5(x²+y²)
=5[(x-y)²+2xy]
=5×﹙1²+2)
=15