设全集I={1,2,3,4,5,6},集合A={1,2,3,4},A交B={1},CI(A并B)={6},求集合BCI代表补集

问题描述:

设全集I={1,2,3,4,5,6},集合A={1,2,3,4},A交B={1},CI(A并B)={6},求集合B
CI代表补集

CI(A并B)={6},所以(A并B)={1,2,3,4,5},
又集合A={1,2,3,4},A交B={1},
所以B={1,5},