因式分解4(a-5)^2+4(a-5)+1
问题描述：
因式分解4(a-5)^2+4(a-5)+1
答
4(a-5)^2+4(a-5)+1
=4[（a-5)²+（a-5）+1/4]
=4[(a-5)+1/2 ]²
=2²[(a-5)+1/2 ]²
=（2a-9）²
答
4(a-5)^2+4(a-5)+1
=【2(a-5)】^2+4(a-5)+1²
=【2（a-5）+1】²
=（2a-9）²
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答
答：
4(a-5)^2+4(a-5)+1
=[2(a-5)]²+2*2(a-5)+1²
=[2(a-5)+1]²
=(2a-10+1)²
=(2a-9)²