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计算：-x(x^2+2x-3)-x^2(x+1)+3x-1 2ab(3/2·a^n-1+1/2b^n-1)-3ab(2/3·a^n-1-b^n-1) [x(x^4-y^4)-3xy（--x(x^2+2x-3)-x^2(x+1)+3x-1 2ab(3/2·a^n-1+1/2b^n-1)-3ab(2/3·a^n-1-b^n-1)[x(x^4-y^4)-3xy（-y)^3·x^2·y

分类: 作业答案 • 2022-02-14 20:36:25
问题描述：

计算：-x(x^2+2x-3)-x^2(x+1)+3x-1 2ab(3/2·a^n-1+1/2b^n-1)-3ab(2/3·a^n-1-b^n-1) [x(x^4-y^4)-3xy（-
-x(x^2+2x-3)-x^2(x+1)+3x-1
2ab(3/2·a^n-1+1/2b^n-1)-3ab(2/3·a^n-1-b^n-1)
[x(x^4-y^4)-3xy（-y)^3·x^2·y

答

-x(x^2+2x-3)-x^2(x+1)+3x-1
=-x³-2x²+3x-x³-x²+3x-1
=-2x³-3x²+6x-1
2ab(3/2·a^n-1+1/2b^n-1)-3ab(2/3·a^n-1-b^n-1)
=3a^nb+ab^n-2a^nb+3ab^n
=a^nb+4ab^n
[x(x^4-y^4)-3xy（-y)^3·x^2·y
=x^5-xy^4+3x^3y^5

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