运用乘法公式计算（x^2-x+1)(x^2+x-1)

分类: 作业答案 • 2022-02-14 20:16:30

问题描述：

答

。。。。写成[x^2-(x-1)][x^2+(x-1)]
平方差公式，得x^4-(x-1)^2=x^4-x^2+2x-1

答

（x^2-x+1)(x^2+x-1)=[x^2-(x-1)][x^2+(x-1)]=(x^2)^2-(x-1)^2=x^4-(x^2-2x+1)=x^4-x^2+2x-1

答

（x^2-x+1)(x^2+x-1)
=x^4-(x-1)^2
=x^4-x^2+2x-1

答

（x^2-x+1)(x^2+x-1)=[x^2-(x-1)](x^2+x-1)=x^4-(x-1)^2
=x^4-x^2+2x-1

答

（x^2-x+1)(x^2+x-1)
=（x^2-(x-1))(x^2+x-1)
=x^4-(x-1)²
=x^4-x²+2x-1

答

（x^2-x+1)(x^2+x-1)
=[x^2-(x-1)](x^2+x-1)
=x^4-(x-1)²
=x^4-（x²-2x+1）
=x^4-x²+2x-1