将下列各式通分:(1)1/a,3/4a²b,1/6ab²c;(2)1/2x-2,1/(x-1)²
问题描述:
将下列各式通分:(1)1/a,3/4a²b,1/6ab²c;(2)1/2x-2,1/(x-1)²
答
(1)1/a,3/4a²b,1/6ab²c通分:(12b²c+9bc+2a)/12a²b²c(2)1/2x-2,1/(x-1)²通分:[(x-1)²+(2x-2)]/(2x-2)(x-1)²=(x²-1)/2(x-1)(x-1)²=(x+1)(x-1)/2(x-1)(x-1)...