化简分式【(x/x+1)+(x/x^2-1)】/(x^2+x/x^2+2x+1)
问题描述：
化简分式【(x/x+1)+(x/x^2-1)】/(x^2+x/x^2+2x+1)
答
原式
=[ (x^2-x+x)/(x+1)(x-1)] / [x(x+1)/(x+1)^2]
=x^2/(x+1)(x-1) * (x+1)/x
=x / (x-1)
答
[(x/x+1)+(x/x²-1)]/(x²+x/x²+2x+1)
=[x(x-1)/(x²-1)+x/(x²-1)]/[x(x+1)/(x+1)²]
=x²/(x²-1)/[x/(x+1)]
=x/(x-1)
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