用分解因式法解下列方程 [1]x(x+1)-5x-5=0 [2](2x+3)^2-(x-1)^2=0 [3](x+根号3)^2=4根号3x
问题描述：
用分解因式法解下列方程 [1]x(x+1)-5x-5=0 [2](2x+3)^2-(x-1)^2=0 [3](x+根号3)^2=4根号3x
答
[1]x(x+1)-5x-5=0
x(x+1)-5(x+1)=0
(x+1)(x-5)=0
x+1=0 x-5=0
x=-1 x=5
[2](2x+3)^2-(x-1)^2=0
(2x+3-x+1)(2x+3+x-1)=0
(x+4)(3x+2)=0
x=-4 x=-2/3
[3](x+根号3)^2=4根号3x
x^2-2根号3x+3=0 (展开后,合并)
(x-根号3)^2=0
x=根号3
答
1.x(x+1)-5x-5=0x(x+1)-5(x+1)=0(x+1)(x-5)=0x=-1或x=52.(2x+3)²-(x-1)²=0[(2x+3)+(x-1)][(2x+3)-(x-1)]=0(3x+2)(x+4)=0x=-2/3或x=-43.(x+√3)²=4√3xx²+2√3x+3=4√3xx²-2√3x+3=0(x-√3)...