(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3
问题描述:
(x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2Y,其中x=-2,y=1/3
答
(x+y)x+(x-y)x-(6x^2y-2xy^2)除以(2y)
=2x^2-(3x^2-xy)
=xy-x^2
=(-2)*1/3-(-2)^2
=-14/3
答
最后的Y是y吗?
如果是,原式化简后为-x^2,结果为-4