您的位置: 首页  >  作业答案  >  物理  >  F-(M+m）g=（M+m)a ····················☆2f-Mg=Ma·····································★联立上面两个星星,怎么得出!F= 〔2（m+M）〕/MF-(M+m）g=（M+m)a ····················☆2f-Mg=Ma·····································★联立上面两个星星，怎么得出！F= 〔2f（m+M）〕/M

F-(M+m）g=（M+m)a ····················☆2f-Mg=Ma·····································★联立上面两个星星,怎么得出!F= 〔2（m+M）〕/MF-(M+m）g=（M+m)a ····················☆2f-Mg=Ma·····································★联立上面两个星星，怎么得出！F= 〔2f（m+M）〕/M

分类: 作业答案 • 2022-02-10 21:59:45
问题描述：

F-(M+m）g=（M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2（m+M）〕/M
F-(M+m）g=（M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星，怎么得出！
F= 〔2f（m+M）〕/M

答

(1)得F=(M+m)(g+a)
(2)得2f=M(g+a) (g+a)=2f/M
代入得
F=2f(M+m)/M

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