16(x+y)的平方-36(x-y)的平方

问题描述:

16(x+y)的平方-36(x-y)的平方

=[4(x+y)+6(x-y)][4(x+y)-6(x-y)]
=(10x-2y)(-2x+10y)
=-4(5x-y)(x-5y)