ρ^2=cos2θ化为直角坐标
问题描述:
ρ^2=cos2θ化为直角坐标
答
p^2=(x/p)^2-(y/p)^2,p^2=x^2+y^2,得x^4+y^4+2(xy)^2+y^2-x^2=0
ρ^2=cos2θ化为直角坐标
p^2=(x/p)^2-(y/p)^2,p^2=x^2+y^2,得x^4+y^4+2(xy)^2+y^2-x^2=0