怎样解一元三次方程?如x^3-6x^2+32=0

问题描述:

怎样解一元三次方程?如x^3-6x^2+32=0

x^3-6x^2+32=0
x^3-8x^2++16x+2x^2-16x+32=0
x(x-4)^2+2(x-4)^2=0
(x+2)(x-4)^2=0
x=-2
或x=4