分解因式:(x+y)的两次(x-y)+(x+y)(x-y)的两次

问题描述:

分解因式:(x+y)的两次(x-y)+(x+y)(x-y)的两次

(x+y)的两次(x-y)+(x+y)(x-y)的两次
=(x+y)(x-y)(x+y+x-y)
=2x(x+y)(x-y)