y=In(x+根号下(x^2+1))求导数
问题描述:
y=In(x+根号下(x^2+1))求导数
答
y′=(1+2x/(2*根号下(x²+1))/(x+根号下(x²+1))
=[(x+根号下(x²+1))/根号下(x²+1)]/(x+根号下(x²+1))
= 1/根号下(x²+1)