N(C):N(H)=80%/12:20%/1=1:3 实验式是CH3
问题描述:
N(C):N(H)=80%/12:20%/1=1:3 实验式是CH3
答
实验式:N(C):N(H)=80%/12:20%/1=1:3 实验式是CH3 该化合物的30*20%==6 6/1==6 即 C2H6 M=30 CxHy x=30*80%/12=2 y=