电阻R1和R2串联,试推导U1=(R1+R2分之R1)×U,U2=(R1+R2分之R2)×U 紧急,
问题描述:
电阻R1和R2串联,试推导U1=(R1+R2分之R1)×U,U2=(R1+R2分之R2)×U 紧急,
答
R=R1+R2 I=U/R=U/(R1+R2) U1=IR1=U/(R1+R2)*R1=R1/(R1+R2)*U 同理U2=IR2=U/(R1+R2)*R2=R2/(R1+R2)*U