求证sin与tan
问题描述:
求证sin与tan
已知3sinB=sin(2A+B),求证tan(A+B)=2tanA
答
3sinB=sin(2A+B)
3sin(A+B-A)=sin(A+b+A)
3sin(A+B)cosA-3cos(A+b)sinA=sin(A+B)cosA+sinAcos(a+b)
2sin(A+b)cosA=4cos(a+b)sina
tan(a+b)=2tana