已知(a-1)2次方+ab-2的绝对值=01/ab加1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2009)(b+2009)
问题描述:
已知(a-1)2次方+ab-2的绝对值=0
1/ab加
1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2009)(b+2009)
答
已知(a-1)2次方+ab-2的绝对值=0
1/ab加
1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2009)(b+2009)