(1+Cos45°-Sin30°)(1-Sin45°+Cos60°)=

问题描述:

(1+Cos45°-Sin30°)(1-Sin45°+Cos60°)=

(1+Cos45°-Sin30°)(1-Sin45°+Cos60°)
=(1+√2/2-1/2)(1-√2/2+1/2)
=(1/2+√2/2)(3/2-√2/2)
=3/4+√2/2-1/2
=1/4+√2/2