呃、、又来求救了,
问题描述：
呃、、又来求救了,
2a（x的平方+1）的平方-8ax的平方
答
2a(x^2+1)^2-8ax^2
=2a[(x^2+1)^2-4x^2]
=2a(x^4+2x^2+1-4x^2)
=2a(x^4-2x^2+1)
=2a(x^2-1)^2
=2a[(x+1)(x-1)]^2
=2a(x+1)^2(x-1)^2顺道再加一题：3x的平方+6xy+3y的平方答对再加5分3x^2+6xy+3y^2=3(x^2+2xy+y^2)=3(x+y)^2