化简1/(2*5)+1/(5*8)+1/(8*11)+…+1/[(3n-1)*(3n+2)]=

问题描述:

化简1/(2*5)+1/(5*8)+1/(8*11)+…+1/[(3n-1)*(3n+2)]=

1/[(3n-1)*(3n+2)]=1/3*{1/(3n-1)-1/(3n+2)}
原式=1/3*{1/2-1/5+1/5-1/8+1/8-1/11+...+1/(3n-1)-1/(3n+2)}
=1/3*{1/2-1/(3n+2)}
=n/(6n+4)