[(m-3)/(m+3)]^2+[(4-2m)/(m+5)]^2=1,解m,详细一点啊
问题描述:
[(m-3)/(m+3)]^2+[(4-2m)/(m+5)]^2=1,解m,详细一点啊
错了是[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1
答
原式➡(m^2-6m+9+16-16m+4m^2)/(m+5)^2=1➡(5m^2-22m+25)=m^2+10m+25➡4m^2-32m=0
➡4m(m-8)=0➡m=0或m=8