在等差数列{an}中,S7=42,Sn=510,第n-3项等于45,求n

问题描述:

在等差数列{an}中,S7=42,Sn=510,第n-3项等于45,求n

an=a1+(n-1)dS7=42(a1+3d)7=42a1+3d=6 (1)Sn =510(2a1+(n-1)d)n/2 = 510(2a1+(n-1)d)n = 1020 (2)a(n-3) =45a1+(n-4)d =45 (3)(3)-(1)(n-7)d = 39 (4)sub (1) into (2)(12-6d+(n-1)d)n = 1020 (12+(n-7)d)n = 1020(1...我就是这样列的啊。。。可是,好吧,把7写成5了。。。还是谢谢啦!