数学x²+y²-10x+12y+61=0,求x+y

问题描述:

数学x²+y²-10x+12y+61=0,求x+y

x²+y²-10x+12y+61=0
(x-5)²+(y+6)²=0
x-5=0,y+6=0
x=5,y=-6
所以
x+y=5-6=-1