(2+1)(2∧2+1)(2∧4)(2∧8+1)(2∧16+1)+1
问题描述:
(2+1)(2∧2+1)(2∧4)(2∧8+1)(2∧16+1)+1
答
(2-1)(2+1)=2^2-1
(2^2-1)(2^2+1)=2^4-1
类似可知
(2+1)(2∧2+1)(2∧4+1)(2∧8+1)(2∧16+1)+1
=(2-1)(2+1)(2∧2+1)(2∧4+1)(2∧8+1)(2∧16+1)+1
=2^32-1+1
=2^32