(1)4(2x-1)^2=1(2) (3x-2)^2=(2x-1)^2(3) 4(2x-1)^2=9(3x-2)^2

问题描述:

(1)4(2x-1)^2=1(2) (3x-2)^2=(2x-1)^2(3) 4(2x-1)^2=9(3x-2)^2

(1)4(2x-1)^2=1
(-3 + 4 x) (-1 + 4 x)
x=3/4 x=1/4
(2) (3x-2)^2=(2x-1)^2
(-1 + x) (-3 + 5 x)=0
x=1 x=3/5
(3) 4(2x-1)^2=9(3x-2)^2
-(-4 + 5 x) (-8 + 13 x)=0
x=4/5 x=8/13