(1)-3a^2b+6ab (2)(x^2-2x)^2+2（x^2-2x）+1 (3)(m+n)(m-n)-(1-2n)
问题描述：
(1)-3a^2b+6ab (2)(x^2-2x)^2+2（x^2-2x）+1 (3)(m+n)(m-n)-(1-2n)
答
(1)-3a²b+6ab =-3ab(a-2b)(2)(x²-2x)²+2（x²-2x）+1 =[(x²-2x)+1]²=[(x-1)²]²=(x-1)(3)(m+n)(m-n)-(1-2n)=m²-n²-1+2n=m²-(n²-2n+1)=m²-(n-1)...(2)(x²-2x)²+2（x²-2x）+1 =[(x²-2x)+1]²=[(x-1)²]²=(x-1)⁴↑正确的