(x-1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)
问题描述:
(x-1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)
题目抄错了、是(x+1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)!!!!!
答
(x-1)/(x²+3x+2)+(x+3)/(x²+7x+12)
=(x-1)/(x+1)(x+2)+(x+3)/(x+3)(x+4)
=(x-1)/(x+1)(x+2)+1/(x+4)
楼主没抄错题么?好吧。真抄错了、是(x+1)/(x^2+3x+2)+(x+3)/(x^2+7x+12)(x+1)/(x²+3x+2)+(x+3)/(x²+7x+12)=(x+1)/(x+1)(x+2)+(x+3)/(x+3)(x+4)=(x+1)/(x+1)(x+2)+1/(x+4)=1/(x+2)+1/(x+4)=(x+4)+(x+2)/(x+2)(x+4)=(x²+2x+4x+8)/(x+2)(x+4)=(x²+6x+8)/(x+2)(x+4)=(x+2)(x+4)/(x+2)(x+4)=1