1.(1/2)^-2+(1/4)^0+(1/2)^-3
问题描述：
1.(1/2)^-2+(1/4)^0+(1/2)^-3
=
=
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2.(-1/3)^-2+(-2又2/3)÷{2^-3x[2-(-2/3)^-2}
=
=
=
3.已知5x-3y+2=0,求10^5x÷10^3y的值
答
1.(1/2)^-2+(1/4)^0+(1/2)^-3
=4+1+8
=13
2.(-1/3)^-2+(-2又2/3)÷{2^-3x[2-(-2/3)^-2}
=9+(-2又2/3)÷{2^-3x[2-9/4]}
=9+(-2又2/3)÷{1/8×(-1/4)}
=9+8/3×32
怀疑原题有问题,孩子的题不会如此大数的
3.已知5x-3y+2=0,求10^5x÷10^3y的值
∵5x-3y+2=0
∴5x-3y=-2
10^5x÷10^3y
=10^(3x-3y)
=10^(-2)
=0.01
我也是孩子爸爸,欢迎追问!