已知奇函数fx满足fx+2=-fx且当x∈(0,1)时fx=2^x则f(7/2)的值为
问题描述:
已知奇函数fx满足fx+2=-fx且当x∈(0,1)时fx=2^x则f(7/2)的值为
答
f(7/2)=f(3/2+2)=-f(3/2)=-f(-1/2 +2)=-[-f(-1/2)]=-f(1/2)=-2^(1/2) =-√2
已知奇函数fx满足fx+2=-fx且当x∈(0,1)时fx=2^x则f(7/2)的值为
f(7/2)=f(3/2+2)=-f(3/2)=-f(-1/2 +2)=-[-f(-1/2)]=-f(1/2)=-2^(1/2) =-√2