(ax+by)²+(ay-bx)²+2(ax+by)(ay-bx) a(ab+bc+ac)-abc 用分解因式法哦
问题描述:
(ax+by)²+(ay-bx)²+2(ax+by)(ay-bx) a(ab+bc+ac)-abc 用分解因式法哦
答
(ax+by)²+(ay-bx)²+2(ax+by)(ay-bx)
=(ax+by+ay-bx)²
a(ab+bc+ac)-abc
=a(ab+bc+ac-bc)
=a(ab+ac)
=a²(b+c)