[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）² 因式分解.
问题描述：
[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）² 因式分解.
答
a(b²2-3a)
答
[（-3ab）²×a³+2a³×（-3ab）³×1/2b]÷（3a²b²）²
=[9a^5b^2+a^3b(-3ab)^3]÷9a^4b^4
=ab^-2-3a^2
=a(b^-2-3a)