(1)3(x-5)²=25-x² (2)2(t-1)²+t=1
问题描述:
(1)3(x-5)²=25-x² (2)2(t-1)²+t=1
答
3(x-5)²+(x+5)(x-5)=0
(x-5)(3x-15+x+5)=0
x=5,x=5/2
2(t-1)²+(t-1)=0
(t-1)(2t-2+1)=0
t=1,t=1/2