已知二次函数y=f（x）满足f（0）=0.5m,且f(x+1)-f(x-1)=4x-2m
问题描述：
已知二次函数y=f（x）满足f（0）=0.5m,且f(x+1)-f(x-1)=4x-2m
求f（x）函数表达式
答
设f(x)=ax^2+bx+c因为f(0)=0.5m所以c=0.5mf(x+1)=a(x+1)^2+b(x+1)+0.5mf(x-1)=a(x-1)^2+b(x-1)+0.5mf(x+1)-f(x-1)=a[(x+1)^2-(x-1)^2]+b[(x+1)-(x-1)]=4ax+2b=4x-2m所以4a=42b=-2ma=1b=-m所以y=x^2-mx+0.5m...